mbus_serial_connect() is ready
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@ -32,65 +32,63 @@
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int
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mbus_serial_connect(mbus_handle *handle)
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{
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// mbus_serial_handle *serial_data;
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//
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// if (device == NULL)
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// {
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// return NULL;
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// }
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//
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// if ((handle = (mbus_serial_handle *)malloc(sizeof(mbus_serial_handle))) == NULL)
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// {
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// fprintf(stderr, "%s: failed to allocate memory for handle\n", __PRETTY_FUNCTION__);
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// return NULL;
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// }
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//
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// handle->device = device; // strdup?
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//
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// //
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// // create the SERIAL connection
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// //
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//
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// // Use blocking read and handle it by serial port VMIN/VTIME setting
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// if ((handle->fd = open(handle->device, O_RDWR | O_NOCTTY)) < 0)
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// {
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// fprintf(stderr, "%s: failed to open tty.", __PRETTY_FUNCTION__);
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// return NULL;
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// }
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//
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// memset(&(handle->t), 0, sizeof(handle->t));
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// handle->t.c_cflag |= (CS8|CREAD|CLOCAL);
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// handle->t.c_cflag |= PARENB;
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//
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// // No received data still OK
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// handle->t.c_cc[VMIN] = 0;
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//
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// // Wait at most 0.2 sec.Note that it starts after first received byte!!
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// // I.e. if CMIN>0 and there are no data we would still wait forever...
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// //
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// // The specification mentions link layer response timeout this way:
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// // The time structure of various link layer communication types is described in EN60870-5-1. The answer time
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// // between the end of a master send telegram and the beginning of the response telegram of the slave shall be
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// // between 11 bit times and (330 bit times + 50ms).
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// //
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// // For 2400Bd this means (330 + 11) / 2400 + 0.05 = 188.75 ms (added 11 bit periods to receive first byte).
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// // I.e. timeout of 0.2s seems appropriate for 2400Bd.
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//
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// handle->t.c_cc[VTIME] = 2; // Timeout in 1/10 sec
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//
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// cfsetispeed(&(handle->t), B2400);
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// cfsetospeed(&(handle->t), B2400);
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//
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//#ifdef MBUS_SERIAL_DEBUG
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// printf("%s: t.c_cflag = %x\n", __PRETTY_FUNCTION__, handle->t.c_cflag);
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// printf("%s: t.c_oflag = %x\n", __PRETTY_FUNCTION__, handle->t.c_oflag);
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// printf("%s: t.c_iflag = %x\n", __PRETTY_FUNCTION__, handle->t.c_iflag);
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// printf("%s: t.c_lflag = %x\n", __PRETTY_FUNCTION__, handle->t.c_lflag);
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//#endif
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//
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// tcsetattr(handle->fd, TCSANOW, &(handle->t));
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mbus_serial_handle *serial_data;
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const char *device;
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struct termios *term;
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if (handle == NULL)
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return 0;
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serial_data = (mbus_serial_handle *) handle->auxdata;
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if (serial_data == NULL || serial_data->device == NULL)
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return 0;
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device = serial_data->device;
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term = &(serial_data->t);
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//
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// create the SERIAL connection
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//
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// Use blocking read and handle it by serial port VMIN/VTIME setting
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if ((handle->fd = open(device, O_RDWR | O_NOCTTY)) < 0)
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{
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fprintf(stderr, "%s: failed to open tty.", __PRETTY_FUNCTION__);
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return 0;
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}
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memset(term, 0, sizeof(*term));
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term->c_cflag |= (CS8|CREAD|CLOCAL);
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term->c_cflag |= PARENB;
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// No received data still OK
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term->c_cc[VMIN] = 0;
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// Wait at most 0.2 sec.Note that it starts after first received byte!!
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// I.e. if CMIN>0 and there are no data we would still wait forever...
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//
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// The specification mentions link layer response timeout this way:
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// The time structure of various link layer communication types is described in EN60870-5-1. The answer time
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// between the end of a master send telegram and the beginning of the response telegram of the slave shall be
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// between 11 bit times and (330 bit times + 50ms).
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//
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// For 2400Bd this means (330 + 11) / 2400 + 0.05 = 188.75 ms (added 11 bit periods to receive first byte).
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// I.e. timeout of 0.2s seems appropriate for 2400Bd.
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term->c_cc[VTIME] = 2; // Timeout in 1/10 sec
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cfsetispeed(term, B2400);
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cfsetospeed(term, B2400);
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#ifdef MBUS_SERIAL_DEBUG
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printf("%s: t.c_cflag = %x\n", __PRETTY_FUNCTION__, term->c_cflag);
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printf("%s: t.c_oflag = %x\n", __PRETTY_FUNCTION__, term->c_oflag);
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printf("%s: t.c_iflag = %x\n", __PRETTY_FUNCTION__, term->c_iflag);
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printf("%s: t.c_lflag = %x\n", __PRETTY_FUNCTION__, term->c_lflag);
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#endif
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tcsetattr(handle->fd, TCSANOW, term);
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return 1;
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}
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//------------------------------------------------------------------------------
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